Question

A 12 pF capacitor is connected to a 50 V battery, the electrostatic energy stored in the capacitor in nJ is

• A. 15
• B. 7.5
• C. 0.3
• D. 150

Answer 1

The Correct Option is A

The energy (E) stored in a capacitor is calculated using the formula $E = \frac{1}{2}CV^2$. In this equation, C represents capacitance, and V represents voltage.

Given C = 12 pF, which is equivalent to 12 × 10^-12 F, and V = 50 V.

The energy stored is computed as $E = \frac{1}{2}(12 \times 10^{-12} \text{ F})(50 \text{ V})^2$. This calculation yields $E = 15 \times 10^{-9} \text{ J}$, which simplifies to 15 nJ.