Question:medium

A \(1000\,\text{kg}\) car moves at \(20\,\text{m s}^{-1}\). The power required to maintain this speed against a resistive force of \(500\,\text{N}\) is

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For motion at constant speed, \[ P=Fv. \] Here \(F\) is the force opposing the motion and \(v\) is the speed of the body.
Updated On: Jul 9, 2026
  • \(5\,\text{kW}\)
  • \(10\,\text{kW}\)
  • \(20\,\text{kW}\)
  • \(50\,\text{kW}\) 

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The Correct Option is B

Solution and Explanation

Concept: Power \(P = Fv\). \(F=500\) N, \(v=20\) m/s. \(P = 500\times20 = 10000\) W = 10 kW.

Step 1:
Write the final answer. \(\boxed{P=10\,\text{kW}}\)
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