Question:medium

A 10 kg object is lifted to a height of 5 meters. Calculate the work done in lifting the object.

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Work done is always calculated as the force applied over a distance. In gravitational work problems, the force is equal to the weight of the object, which is the product of mass and gravitational acceleration.
Updated On: Nov 26, 2025
  • \( 500 \, \text{J} \)
  • \( 100 \, \text{J} \)
  • \( 200 \, \text{J} \)
  • \( 150 \, \text{J} \)
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The Correct Option is A

Solution and Explanation

The work done against gravity is calculated using \( W = m \cdot g \cdot h \). Here, \( W \) is work, \( m \) is mass, \( g \) is gravitational acceleration (approx. \( 9.8 \, \text{m/s}^2 \)), and \( h \) is height. Given \( m = 10 \, \text{kg} \) and \( h = 5 \, \text{m} \), the calculation is \( W = 10 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 5 \, \text{m} = 490 \, \text{J} \). This calculated value of \( 490 \, \text{J} \) is close to the provided correct answer of \( 500 \, \text{J} \). This discrepancy suggests potential rounding of the gravitational constant or other simplifications. Therefore, \( 500 \, \text{J} \) is the most suitable answer.

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