Question:medium

64 identical spheres each having charge q coalesce to form one big sphere. Find the ratio of the surface charge density of the big sphere to that of small sphere

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For $n$ coalescing identical drops, general relations are:
Radius: $R = n^{1/3}r$
Charge: $Q = nq$
Potential: $V = n^{2/3}v$
Surface charge density: $\sigma_{\text{big}} = n^{1/3} \sigma_{\text{small}}$ (Here $64^{1/3} = 4$).
Updated On: Apr 21, 2026
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