Question

The value by which free fall acceleration differs from acceleration due to gravity at the equator is:
 

• A. \(+\omega^2 R\)
• B. \(-\omega^2 R\)
• C. \(+2\omega^2 R\)
• D. \(-2\omega^2 R\)

Hint:

At the equator: centripetal effect is maximum (\(\omega^2 R \approx 0.034\) m/s\(^2\)), so \(g_{\text{eff}}\) is minimum (\(\approx 9.78\) m/s\(^2\)).
At the poles: \(\phi = 90^\circ\), \(\cos\phi = 0\), so centripetal effect is zero and \(g_{\text{eff}} = g\) (\(\approx 9.83\) m/s\(^2\)).

Answer 1

The Correct Option is B