Question

\(540\) gram of ice at \(0^{\circ }\)C is mixed with \(540\) gram of water at \(90^{\circ }\)C. The final temperature of the mixture will be [Latent heat of fusion of water = 80 cal/g]

• A. \(10^{\circ }\)C
• B. \(15^{\circ }\)C
• C. \(5^{\circ }\)C
• D. \(30^{\circ }\)C

Hint:

Check first whether all the ice can melt using the heat from the hot water.

Answer 1

The Correct Option is C

Step 1: Equation
$540\times1\times(90-T)=540\times80+540\times1\times(T-0)$.

Step 2: Simplify
$90-T=80+T$.

Step 3: Result
$2T=10$, so $T=5^{\circ}$C.

Final Answer:
The mixture settles at 5 degrees Celsius. \[ \boxed{\text{(C) }5^{\circ}\text{C}} \]