Question

18 g of glucose (molar mass = 180 g/mol) is dissolved in water to prepare 500 ml solution at \(15^{\circ}\text{C}\). Calculate the osmotic pressure of the solution. [\(R = 0.0821 \text{L atm K}^{-1} \text{mol}^{-1}\)]

• A. \(1.65 \text{atm}\)
• B. \(4.73 \text{atm}\)
• C. \(5.57 \text{atm}\)
• D. \(2.34 \text{atm}\)

Hint:

Use pi = CRT with temperature in kelvin.

Answer 1

The Correct Option is B

Step 1: Use the van t Hoff relation
$\pi V = nRT$, so $\pi = \frac{nRT}{V}$.

Step 2: Substitute
$\pi = \frac{0.1 \times 0.0821 \times 288}{0.5} = \frac{2.364}{0.5} = 4.73$ atm.

Step 3: Answer
Option (B).

Final Answer:
4.73 atm. \[ \boxed{\text{(B)}\ 4.73\ \text{atm}} \]