Question:medium

$100 \text{ mL}$ of $0.05 \text{ M } \text{Cu}^{2+}$ aqueous solution is added to $1 \text{ L}$ of $0.1 \text{ M } \text{KI}$ solution. The number of moles of $\text{I}_2$ and $\text{Cu}_2\text{I}_2$ formed are respectively

Show Hint

For reactions involving stoichiometry, the first step is always to write and balance the chemical equation. Then, use the mole ratio to identify the limiting reagent, which controls the amount of product formed. The final calculation is based on the limiting reagent.

Updated On: Mar 30, 2026

$2.5\times 10^{-3}, 5\times 10^{-3}$
$5\times 10^{-3}, 5\times 10^{-3}$
$5\times 10^{-3}, 2.5\times 10^{-3}$
$2.5\times 10^{-3}, 2.5\times 10^{-3}$

Show Solution

The Correct Option is D

Solution and Explanation

Was this answer helpful?

0

Top Questions on Stoichiometry and Stoichiometric Calculations

Questions Asked in TS EAMCET exam

If $\omega \neq 1$ is a cube root of unity, then one root among the $7^{th}$ roots of $(1+\omega)$ is

TS EAMCET - 2025
Complex numbers

If $A = \begin{pmatrix} 1 & 2 & 3 \\ 2 & 1 & 1 \\ 1 & 3 & 1 \end{pmatrix}$ and $B = \begin{pmatrix} 2 & 3 & 4 \\ 3 & 2 & 2 \\ 2 & 4 & 2 \end{pmatrix}$, then $\sqrt{|\text{Adj}(AB)|} =$

TS EAMCET - 2025
Matrices and Determinants

If \( p_1, p_2, p_3 \) are the altitudes and \( a=4, b=5, c=6 \) are the sides of a triangle ABC, then \( \frac{1}{p_1^2} + \frac{1}{p_2^2} + \frac{1}{p_3^2} = \)

TS EAMCET - 2025
Geometry

If \(\alpha, \beta, \gamma, \delta, \epsilon\) are the roots of the equation \(x^5 + x^4 - 13x^3 - 13x^2 + 36x + 36 = 0\) and \(\alpha<\beta<\gamma<\delta<\epsilon\) then \( \frac{\epsilon}{\alpha} + \frac{\delta}{\beta} + \frac{1}{\gamma} = \)

TS EAMCET - 2025
Algebra