Question

$100 \text{ mL}$ of $0.05 \text{ M } \text{Cu}^{2+}$ aqueous solution is added to $1 \text{ L}$ of $0.1 \text{ M } \text{KI}$ solution. The number of moles of $\text{I}_2$ and $\text{Cu}_2\text{I}_2$ formed are respectively

• A. $2.5\times 10^{-3}, 5\times 10^{-3}$
• B. $5\times 10^{-3}, 5\times 10^{-3}$
• C. $5\times 10^{-3}, 2.5\times 10^{-3}$
• D. $2.5\times 10^{-3}, 2.5\times 10^{-3}$

Hint:

For reactions involving stoichiometry, the first step is always to write and balance the chemical equation. Then, use the mole ratio to identify the limiting reagent, which controls the amount of product formed. The final calculation is based on the limiting reagent.

Answer 1

The Correct Option is D