Step 1: Define molarity and dilution principles.
The molarity of the final solution is determined using the dilution equation:
\[M_1 V_1 + M_2 V_2 = M_3 (V_1 + V_2)\]
Here, \(M_1\) and \(M_2\) represent the initial molarities, and \(V_1\) and \(V_2\) are the volumes of the solutions being combined.
Step 2: Input the provided data.
\[(0.5 \, \text{M} \times 10 \, \text{ml}) + (0.3 \, \text{M} \times 30 \, \text{ml}) = M_3 \times (10 \, \text{ml} + 30 \, \text{ml})\]
\[(5) + (9) = M_3 \times 40\]
\[M_3 = \frac{14}{40} = 0.40 \, \text{M}\]
Final Result: \[\boxed{\text{A) 0.40 M}}\]
Consider the following compounds:
(i) CH₃CH₂Br
(ii) CH₃CH₂CH₂Br
(iii) CH₃CH₂CH₂CH₂Br
Arrange the compounds in the increasing order of their boiling points.
Assertion (A): The boiling points of alkyl halides decrease in the order: RI>RBr>RCl>RF.
Reason (R): The boiling points of alkyl chlorides, bromides and iodides are considerably higher than that of the hydrocarbon of comparable molecular mass.
Arrange the following compounds in increasing order of their boiling point: \[ \text{(CH}_3\text{)}_2\text{NH, CH}_3\text{CH}_2\text{NH}_2, \text{CH}_3\text{CH}_2\text{OH} \]