Question:medium

1 g of fuming H\(_2\)SO\(_4\) (oleum: mixture of H\(_2\)SO\(_4\) and SO\(_3\) having formula H\(_2\)S\(_2\)O\(_7\)) is diluted with H\(_2\)O. This solution is completely neutralised by 26.7 mL of 0.8 N NaOH. Find the percentage of free SO\(_3\) in the oleum.

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Oleum is H\(_2\)SO\(_4\) + SO\(_3\). Equivalent weight of SO\(_3\) = 80/2 = 40.
Updated On: Apr 23, 2026
  • 20.73%
  • 43.80%
  • 79.27%
  • 60.74%
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The Correct Option is A

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