Question:medium

0.1 m$^{3}$ of water at $80^{\circ}C$ is mixed with 0.3 m$^{3}$ of water at $60^{\circ}C$. The final temperature of the mixture is

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When mixing the same substance, $t_{final} = \frac{m_1t_1 + m_2t_2}{m_1 + m_2}$.
Updated On: Apr 10, 2026
  • $65^{\circ}C$
  • $70^{\circ}C$
  • $60^{\circ}C$
  • $75^{\circ}C$
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The Correct Option is A

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