An alpha particle moves towards a fixed nucleus carrying charge \(Ze\), with initial speed \(v_0\) and impact parameter \(b\). Starting from a large distance from the nucleus, its distance of closest approach is \(r_m\) and its speed there is \(v_m\). Then which of the following options is correct?
\( \left(k = \dfrac{1}{4\pi\epsilon_0} \text{ and } r_0 = k\dfrac{Ze^2}{mv_0^2}\right) \)