List of top Physics Questions on coulombs law

Five point charges, each of value \(+q\), are placed on five vertices of a regular hexagon of side \(L\). What is the magnitude of the force on a point charge \(-q\) placed at the centre of the hexagon?
The electrostatic force between two charges $q_1$ and $q_2$ separated by a distance $r$ in vacuum is $F$. If a dielectric medium of dielectric constant $K$ is introduced between them, the new force is
Two charges \( q_1 \) and \( q_2 \) are placed at a distance \( r \). If the distance between them is doubled, the electrostatic force between them becomes:
Two point charges \(q_1\) and \(q_2\) are \(r\) cm apart in a vacuum with force \(F\). What is the force if they are placed in a medium with dielectric constant \(K = 5\) at distance \(r/5\)?
If the distance between two charges is doubled, what happens to the Coulomb force?
If the distance between two charges is doubled, the Coulomb force becomes:
Two equally charged small balls placed at a fixed distance experience a force 'F'. A similar uncharged ball after touching one of them is placed at the middle point between the two balls. The force experienced by this ball is ______.
Force between two charges \( +8\,\mu C \) and \( +2\,\mu C \) is \( 16\,N \). If the charges are brought into contact and then separated by the same distance, the force between them is
Which one of the following pairs of charges separated by the same distance r will experience a maximum force?
A given charge \( Q \) is divided into two parts which are then kept at a distance \( d \) apart. The electrostatic force between them will be maximum if the two parts are
The electrostatic force between two point charges at a distance of separation \(d\) is \(F\). If one of the charge is moved away by a distance \(d/2\) then the force between them is
Two charges of \( +2 \, \mu\text{C} \) and \( -2 \, \mu\text{C} \) are placed 1 meter apart. What is the force between them?
Two point charges \( +2 \, \mu\text{C} \) and \( -3 \, \mu\text{C} \) are placed 10 cm apart in vacuum. What is the electrostatic force between them?
Two point charges \(+2 \, \mu\text{C}\) and \(-2 \, \mu\text{C}\) are placed 0.1 m apart in air. What is the electrostatic force between them?
Two identical conducting spheres P and S with charge Q on each, repel each other with a force 16N. A third identical uncharged conducting sphere R is successively brought in contact with the two spheres. The new force of repulsion between P and S is :
Force between two point charges \( q_1 \) and \( q_2 \) placed in vacuum at \( r \) cm apart is \( F \). Force between them when placed in a medium having dielectric \( K = 5 \) at \( r/5 \) cm apart will be:
If two charges $q _1$ and $q _2$ are separated with distance ' $d$ ' and placed in a medium of dielectric constant $K$ What will be the equivalent distance between charges in air for the same electrostatic force?
A stream of a positively charged particles having $\frac{q}{ m }=2 \times 10^{11} \frac{ C }{ kg }$ and velocity $\vec{v}_0=3 \times 10^7 \hat{i} m / s$ is deflected by an electric field $18 kV / m$ The electric field exists in a region of $10 cm$ along $x$ direction Due to the electric field, the deflection of the charge particles in the $y$ direction is___ $mm$
Two point charges $+3 \; \mu\text{C}$ and $+8 \; \mu\text{C}$ repel each other with a force of $40 \text{ N}$. If a charge of $-5 \; \mu\text{C}$ is added to each of them, then the force between them will become
Two positive ions, each carrying a charge $q$ are separated by a distance $d$. If $F$ is the force of repulsion between the ions, the number of electrons missing from each ion will be ($\varepsilon_0$ = permittivity of free space, $e$ = charge on an electron)
'F' is the force between the two identical charged particles placed at a distance 'Y' from each other. If the distance between the charges is reduced to half the previous distance then force between them becomes
'F' is the force between the two identical charged particles placed at a distance 'Y' from each other. If the distance between the charges is reduced to half the previous distance then force between them becomes
Given that \(q_1 + q_2 = q\). For what ratio \(q_1/q_2\) will the force between \(q_1\) and \(q_2\) be maximum ?
Two identical charged spheres are suspended from a common point by massless strings of length l, initially at a distance d(d≪ l) apart because of their mutual repulsion. The charges begin to leak from both the spheres at a constant rate. As a result, the spheres approach each other with velocity v. Then v varies as a function of the distance x between the spheres as:
Two point charges $A$ and $B$, having charges $+ Q$ and $- Q$ respectively, are placed at certain distance apart and force acting between them is $F$. If $25\%$ charge of $A$ is transferred to $B$. then force between the charges become