List of top Physics Questions on Energy in simple harmonic motion asked in MHT CET

A particle performs linear S.H.M. with potential energy \(U = 0.1\pi^2 x^2\). If the mass is \(20\,g\), what is its frequency?

Potential energy of a particle performing linear S.H.M is \(0.1\pi^{2}x^{2}\) joule. If the mass is \(20\,g\), what is the frequency of S.H.M?

Calculate the ratio of potential energy to kinetic energy at time \(t=\dfrac{T}{6}\) for a particle starting SHM from its mean position.

A particle starts oscillating simple harmonically from its mean position with time period \(T\); find the ratio of potential energy to kinetic energy at time \(t = \frac{T}{6}\).

A particle in SHM has a speed of \(6\,cm/s\) at the mean position and an amplitude of \(4\,cm\). Find its position when its velocity is \(2\,cm/s\).

A particle starts oscillating simple harmonically from its mean position with time period 'T'. At time $t = T/6$, the ratio of the potential energy to kinetic energy of the particle is \dots

A simple pendulum starts oscillating simple harmonically from its mean position (\(x = 0\)) with amplitude ' \(a\) ' and periodic time ' \(T\) '. The magnitude of velocity of pendulum at \(x = \frac{a}{2}\) is

A simple pendulum starts oscillating simple harmonically from its mean position (\(x = 0\)) with amplitude ' \(a\) ' and periodic time ' \(T\) '. The magnitude of velocity of pendulum at \(x = \frac{a}{2}\) is

A simple pendulum starts oscillating simple harmonically from its mean position (\(x = 0\)) with amplitude ' \(a\) ' and periodic time ' \(T\) '. The magnitude of velocity of pendulum at \(x = \frac{a}{2}\) is

A particle starts from mean position and performs S.H.M. with period 6 second. At what time its kinetic energy is $50\%$ of total energy? \( (\cos 45^\circ = \frac{1}{\sqrt{2}}) \)

Find the ratio of K.E. and P.E. when a particle performs SHM when it is at \( \frac{1}{n} \) times of its amplitude from the mean position.

A mass $0.4\ \text{kg}$ performs S.H.M. with a frequency $\frac{16}{\pi}\ \text{Hz}$. At a certain displacement it has kinetic energy $2\ \text{J}$ and potential energy $1.2\ \text{J}$. The amplitude of oscillation is

A body of mass '$m$' performs linear S.H.M. given by the equation $x = P \sin \omega t + Q \sin \left(\omega t + \frac{\pi}{2}\right)$. The total energy of the particle at any instant is

A body is performing S.H.M. of amplitude 'A'. The displacement of the body from a point where kinetic energy is maximum to a point where potential energy is maximum, is

A particle performing S.H.M. when displacement is 'x', the potential energy and restoring force acting on it are denoted by 'E' and 'F' respectively. The relation between x, E and F is

An object executes SHM along $x$-axis with amplitude $0.06 \text{ m}$. At certain distance $x$ metre from mean position, it has kinetic energy $10 \text{ J}$ and potential energy $8 \text{ J}$. The distance $x$ will be