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The variance of first n even natural numbers is
$\frac{n^2 - 1}{4}$
. The sum of first n natural numbers is
$\frac{n(n + 1)}{2}$
and the sum of squares of first n natural numbers is
$\frac{n(n + 1)(2n +1)}{6}$
.
JEE Main - 2009
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