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List of top Chemistry Questions on Work done in Thermodynamics asked in JEE Advanced

An ideal gas (\(0.5\) mol), initially at \(2\) bar pressure, is compressed at a constant temperature of \(600\ \text{K}\) in two steps: first, against a constant external pressure of \(P\) bar \((2 < P < 8)\), and then against constant external pressure of \(8\) bar. At each step, the compression is stopped only when the pressure of the gas becomes equal to the external pressure. The total work done on the gas in these steps is \(W\). Considering all possible values of \(P\ (2 < P < 8)\) and taking the gas constant as \(R\) (in \(\text{J K}^{-1}\text{mol}^{-1}\)), the minimum value of \(|W|\) (in J) is equal to:
  • JEE Advanced - 2026
  • JEE Advanced
  • Chemistry
  • Work done in Thermodynamics
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