The final product (D) in the above conversion is:
\[
\text{Me} - \text{CH}_3 \xrightarrow{\text{H}_2, \text{(mol)}, \text{Ni}} \text{(A)} \xrightarrow{\text{PhCO}_2\text{H}, \text{H}_2\text{O}} \text{(B)} \xrightarrow{\text{NaOEt, EtOH}} \text{(C)} \xrightarrow{\text{EtMgBr, Et}_2\text{O}} \xrightarrow{\text{H}_2\text{O}} \text{(D)}
\]
The options are:
