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List of top Mathematics Questions on sets asked in BITSAT
Number of subsets of set of letters of word 'MONOTONE' is:
BITSAT - 2024
BITSAT
Mathematics
sets
In a statistical investigation of 1003 families of Calcutta, it was found that 63 families have neither a radio nor a TV, 794 families have a radio, and 187 have a TV. The number of families having both a radio and a TV is:
BITSAT - 2024
BITSAT
Mathematics
sets
If \( a>0, b>0, c>0 \) and \( a, b, c \) are distinct, then \( (a + b)(b + c)(c + a) \) is greater than:
BITSAT - 2024
BITSAT
Mathematics
sets
The modulus of the complex number \( z \) such that \( |z + 3 - i| = 1 \) and \( \arg(z) = \pi \) is equal to:
BITSAT - 2024
BITSAT
Mathematics
sets
Let A,B,C be finite sets. Suppose that n(A)=10, n(B)=15, n(C)=20, n(A∩ B)=8 and n(B∩ C)=6. Then the possible value of n(A∪ B∪ C) is
BITSAT - 2021
BITSAT
Mathematics
sets
Two finite sets have m and n elements. The number of subsets of the first set is 112 more than that of the second. The values of m and n respectively are:
BITSAT - 2020
BITSAT
Mathematics
sets
Universal set:
\[ U = \{ x \mid x^5 - 6x^4 + 11x^3 - 6x^2 = 0 \} \]
Subsets:
\[ A = \{ x \mid x^2 - 5x + 6 = 0 \}, \quad B = \{ x \mid x^2 - 3x + 2 = 0 \} \]
Find:
\[ (A \cap B)' \]
BITSAT - 2019
BITSAT
Mathematics
sets
Let \(A, B, C\) be finite sets. Suppose that \(n(A) = 10\), \(n(B) = 15\), \(n(C) = 20\), \(n(A \cap B) = 8\), and \(n(B \cap C) = 9\). Then the possible value of \(n(A \cup B \cup C)\) is
BITSAT - 2017
BITSAT
Mathematics
sets
Two finite sets have m and n elements. The number of subsets of the first set is 112 more than that of the second set. The values of m and n respectively are:
BITSAT - 2016
BITSAT
Mathematics
sets
Universal set, \[ U=\{x\mid x^5-6x^4+11x^3-6x^2=0\}; \quad A=\{x\mid x^2-5x+6=0\}; \quad B=\{x\mid x^2-3x+2=0\}. \] What is \((A\cap B)'\)?
BITSAT - 2015
BITSAT
Mathematics
sets
The set \((A\setminus B)\cup(B\setminus A)\) is equal to:
BITSAT - 2014
BITSAT
Mathematics
sets
Let A and B be two sets then \( (A \cup B) \cup (A \cap B) \) is equal to:
BITSAT - 2012
BITSAT
Mathematics
sets
Let A=\x:x R, |x|<1 B=\x:x R, |x-1| 1 and A B=R-D, then the set D is
BITSAT - 2010
BITSAT
Mathematics
sets