A body of mass $5\text{ kg}$ is projected vertically upwards from a point $X$ from the ground with an initial speed of $20\text{ ms}^{-1}$. It rises to a point $Y$ where its kinetic energy is reduced to $400\text{ J}$. If the body experiences a constant air resistance of $10\text{ N}$ throughout its motion, then the vertical distance between $X$ and $Y$ is (Acceleration due to gravity $=10\text{ ms}^{-2}$)