List of top Physics Questions on Projectile motion asked in TS EAMCET

The time taken by a projectile to reach the maximum height is 4 s. If the horizontal distance between the positions of the projectile at times 3 s and 5 s is 60 m, then its velocity of projection is (Acceleration due to gravity $=10~ms^{-2}$)

If minimum velocity of a projectile is \(15\text{ ms}^{-1}\) and maximum height reached is \(20\text{ m}\), then velocity of projection is (\(g=10\text{ ms}^{-2}\))