Question

Z in the above reaction sequence is :-

• A. $ CH_3 CH_2 CH_2NHCOCH_3 $
• B. $ CH_3 CH_2 CH_2NH_2 $
• C. $ CH_3 CH_2 CH_2 CONHCH_3 $
• D. $ CH_3 CH_2 CH_2 CONHCOCH_3 $

Answer 1

The Correct Option is A

To determine the product Z in the given reaction sequence, we need to analyze the step-by-step transformation of the reactants. Firstly, let's write down the sequence of reactions that typically could lead to the formation of the desired amide.

1. We start with a simple alkyl amine, likely as CH_3CH_2CH_2NH_2, which is propylamine.
2. The reaction sequence given generally suggests an acetylation process. In such reactions, the amine reacts with acetic anhydride or acetyl chloride to form an amide.
3. In acetylation, the amino group (NH_2) of propylamine reacts with acetic anhydride (or acetyl chloride) to form an amide bond, specifically NHCOCH_3.
4. This results in the formation of CH_3CH_2CH_2NHCOCH_3, which is propylacetamide.

Therefore, the correct product Z in the reaction sequence is CH_3CH_2CH_2NHCOCH_3. This is an acetylated amine, where the acetyl group is added to the nitrogen of the amine.

Now, let's rule out the other options:

• CH_3CH_2CH_2NH_2 is the starting amine, not the final product.
• CH_3CH_2CH_2CONHCH_3 is a misplaced acyl group, forming an incorrect structure.
• CH_3CH_2CH_2CONHCOCH_3 represents a diacylation or an anhydride form, which is not typically formed directly in a simple amine acetylation reaction.

The correct answer is CH_3CH_2CH_2NHCOCH_3, which is the given correct choice in the options.