To ascertain the quantity of turns in the solenoid, the inductance \( L \) formula is utilized:
Where:
- represents inductance (0.016 H)
- denotes permeability of free space (\(4π \times 10^{-7} \, \text{Tm/A}\))
- is the number of turns
- is the cross-sectional area
- is the solenoid's length (0.81 m)
The solenoid's cross-sectional area \( A \) is calculated as:
Given a radius \( r = 0.02 \, \text{m} \), the area is computed:
Substituting values to find \( A \):
Inserting this into the inductance formula yields:
Rearranging to solve for \( N^2 \):
Finally, solving for \( N \):
The computed number of turns is approximately \( N \approx 2976 \).