Question:medium

You are required to design an air-filled solenoid of inductance 0.016 H having a length 0.81 m and radius 0.02 m. The number of turns in the solenoid should be:

Show Hint

For air-filled solenoids, permeability \( \mu_r = 1 \). Always check the unit consistency when using formulas.
Updated On: Feb 19, 2026
  • 2592
  • 2866
  • 2976
  • 3140
Show Solution

The Correct Option is C

Solution and Explanation

To ascertain the quantity of turns in the solenoid, the inductance \( L \) formula is utilized:
L=μN2Al
Where:
  • L represents inductance (0.016 H)
  • μ denotes permeability of free space (\(4π \times 10^{-7} \, \text{Tm/A}\))
  • N is the number of turns
  • A is the cross-sectional area
  • l is the solenoid's length (0.81 m)
The solenoid's cross-sectional area \( A \) is calculated as:
A=πrr2
Given a radius \( r = 0.02 \, \text{m} \), the area is computed:
A=π(</mo>0.02)2
Substituting values to find \( A \):
=3.1416×(</mo>0.02)2=1.25664×10-3 m2
Inserting this into the inductance formula yields:
0.016=(</mo>4π×10-7)N2(</mo>1.25664×10-3)0.81
Rearranging to solve for \( N^2 \):
NN2=0.0160.81(</mo>4π×10-7)÷(</mo>1.25664×10-3)
Finally, solving for \( N \):
N=0.0160.81(</mo>4π×10-7)÷(</mo>1.25664×10-3)
The computed number of turns is approximately \( N \approx 2976 \).
Was this answer helpful?
4