Question:medium

\(y_1 = 4\sin(\Omega t + kx)\), \(y_2 = -4\cos(\Omega t + kx)\). The phase difference is

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\(-\cos\theta = \sin(\theta - \pi/2) = \sin(\theta + 3\pi/2)\).
Updated On: Apr 7, 2026
  • \(\pi/2\)
  • \(3\pi/2\)
  • \(\pi\)
  • zero
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The Correct Option is B

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