$XeF_6$ on partial hydrolysis with water produces a compound $'X'$. The same compound $'X'$ is formed when $XeF_6$ reacts with silica. The compound $'X'$ is :

Question

Statement-I: An element ‘X’ of P-block forms a hydride H–X, which has the longest bond length, then element ‘X’ will have the shortest covalent radius.
Statement-II: An element ‘E’ of Group 15 forms hydride EH$_3$, that has least B.P. The maximum covalency of E is 4.

Answer 1

Xenon hexafluoride ($ XeF_6 $) undergoes partial hydrolysis when it is reacted with water, which results in the formation of xenon oxyfluoride ($ XeOF_4 $). Let's go through the logical steps and chemical reaction involved:

Step 1: Understand Partial Hydrolysis

When $ XeF_6 $ reacts with water, a hydrolysis reaction occurs. In partial hydrolysis, not all fluoride ions are replaced by hydroxyl ions, leading to the formation of an oxyfluoride complex rather than complete hydrolysis to form xenon oxide and HF.

Step 2: Reaction Involved

The reaction for partial hydrolysis of $ XeF_6 $ can be represented as:

XeF_6 + H_2O \rightarrow XeOF_4 + 2HF

Step 3: Result of the Reaction

From this reaction, you can see that xenon oxyfluoride ($ XeOF_4 $) is produced along with hydrofluoric acid (HF).

Conclusion

Therefore, the compound formed when $ XeF_6 $ undergoes partial hydrolysis with water is XeOF_4. The correct answer is XeOF_4.

Answer 2