Question:medium
\(x = \frac{1 + \cos 2\theta}{\tan \theta - \sec \theta}\) and \(y = \frac{\tan \theta + \sec \theta}{\sec^2 \theta}\), then \(\frac{y}{x} =\)
\(x = \frac{1 + \cos 2\theta}{\tan \theta - \sec \theta}\) and \(y = \frac{\tan \theta + \sec \theta}{\sec^2 \theta}\), then \(\frac{y}{x} =\)
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\(\sin^2 \theta - 1 = -\cos^2 \theta\).
Updated On: Apr 25, 2026
- \(\frac{1}{2}\)
- 2
- -2
- \(-\frac{1}{2}\)
- 1
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The Correct Option is D
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