Analysis of the Reaction:
This question deals with the Nitration of Phenol. The product depends on the concentration of the acid used.
Reaction with Dilute $HNO_3$:
When phenol is treated with dilute nitric acid at low temperature (298 K), it undergoes mono-nitration to yield a mixture of ortho- and para- isomers.
(A) o-Nitrophenol: The $-NO_2$ group attaches at the ortho position (adjacent to $-OH$).
(B) p-Nitrophenol: The $-NO_2$ group attaches at the para position (opposite to $-OH$).
Reaction with Concentrated $HNO_3$:
With concentrated nitric acid, the reaction is vigorous, and poly-nitration occurs at all activating positions (ortho and para).
(C) 2,4,6-Trinitrophenol: Commonly known as Picric Acid.
Structures:
(A): o-Nitrophenol ($C_6H_4(OH)(NO_2)$ - ortho isomer)
(B): p-Nitrophenol ($C_6H_4(OH)(NO_2)$ - para isomer)
(C): 2,4,6-Trinitrophenol (Picric Acid)