Question:medium
Work function \(\phi\) of a metal is \(9.53 \times 10^{-19}\) J, and the frequency of incident light is \(3.5 \times 10^{16}\) Hz. Find the kinetic energy of photoelectron. (Given Planck's constant \(h = 6.62 \times 10^{-34}\) Js) ?
Work function \(\phi\) of a metal is \(9.53 \times 10^{-19}\) J, and the frequency of incident light is \(3.5 \times 10^{16}\) Hz. Find the kinetic energy of photoelectron. (Given Planck's constant \(h = 6.62 \times 10^{-34}\) Js) ?
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For photoelectric effect problems:
\[
K.E.=h\nu-\phi
\]
Always calculate photon energy first and then subtract the work function.
Updated On: May 22, 2026
- \(2.8 \times 10^{-17}\) J
- \(5.2 \times 10^{-17}\) J
- \(2.2 \times 10^{-17}\) J
- \(9.1 \times 10^{-17}\) J
Show Solution
The Correct Option is C
Solution and Explanation
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