Question

Work done to get ' \(n\) ' spherical drops of equal size from a single spherical drop of water, is proportional to

• A. \(\left( \frac{1}{n^{2/3}} - 1 \right)\)
• B. \(\left( \frac{1}{n^{1/3}} - 1 \right)\)
• C. \(n^{1/3} - 1\)
• D. \(n^{4/3} - 1\)

Hint:

Key: More drops $\rightarrow$ more surface area $\rightarrow$ more work

Answer 1

The Correct Option is C