Question:hard

With reference to lead poisoning, match List I (Agent) with List II (Amount) and select the correct answer using the codes given below the list.
List I (Agent)List II (Amount)
A. Coproporphyrin in urine1. > 70 mcg/100 ml
B. Aminolevulinic acid in urine2. > 5 mg/L
C. Lead in urine3. > 150 mcg/L
D. Lead in blood4. > 0.8 mg/L

Show Hint

Blood lead above 70 mcg/100 ml is the classic lead poisoning cut-off; match the rest around it.
Updated On: Jul 7, 2026
  • A-1, B-2, C-4, D-3
  • A-3, B-4, C-2, D-1
  • A-1, B-4, C-2, D-3
  • A-3, B-2, C-4, D-1
Show Solution

The Correct Option is D

Solution and Explanation

Step 1: List the four markers.
We are matching four lead poisoning tests, coproporphyrin in urine, ALA in urine, lead in urine and blood lead, to four cut off values.

Step 2: Anchor on the value you know best.
Blood lead over 70 mcg/100 ml is the classic textbook alert value for lead toxicity. That fixes D to value 1.

Step 3: Work through the rest.
Urine lead crossing 0.8 mg/L signals heavy exposure, fixing C to value 4. Urinary ALA rising past 5 mg/L reflects blocked heme production, fixing B to value 2. That leaves urinary coproporphyrin above 150 mcg/L for A, fixing A to value 3.

Step 4: Match to the given codes.
A-3, B-2, C-4, D-1 is exactly the fourth code option listed in the question.

Step 5: Conclude.
\[ \boxed{\text{A-3, B-2, C-4, D-1}} \]
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