Question:medium

With gradual increase in frequency of an a.c. supply, the impedance of an LCR series circuit

Show Hint

Impedance falls to its minimum at resonance and then rises.
Updated On: Oct 1, 2026
  • increases
  • decreases
  • remains constant
  • first decreases, becomes minimum and then increases
Show Solution

The Correct Option is D

Solution and Explanation

Step 1: Shape of the curve:
Current in an LCR circuit peaks at resonance, so the impedance $Z = V/I$ is lowest there.

Step 2: Both sides:
Away from resonance, in either direction, $|X_L - X_C|$ grows, so $Z$ grows.

Step 3: Result:
Rising frequency takes the circuit through the minimum, option (D).

Final Answer:
Impedance falls, reaches a minimum, then rises. \[ \boxed{\text{(D) }\text{first decreases, becomes minimum and then increases}} \]
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