Step 1: Shape of the curve:
Current in an LCR circuit peaks at resonance, so the impedance $Z = V/I$ is lowest there.
Step 2: Both sides:
Away from resonance, in either direction, $|X_L - X_C|$ grows, so $Z$ grows.
Step 3: Result:
Rising frequency takes the circuit through the minimum, option (D).
Final Answer:
Impedance falls, reaches a minimum, then rises.
\[ \boxed{\text{(D) }\text{first decreases, becomes minimum and then increases}} \]