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Why do transition metals have high enthalpy of atomization? Which element of the 3d-series has the lowest enthalpy of atomization?
Why do transition metals have high enthalpy of atomization? Which element of the 3d-series has the lowest enthalpy of atomization?
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Zinc (Zn) has a fully filled \( 3d^{10} \) configuration, so it has fewer unpaired electrons and weaker bonding, leading to the lowest enthalpy of atomization in the 3d series.
Updated On: Jan 13, 2026
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Solution and Explanation
- Transition metals exhibit high enthalpies of atomization because numerous unpaired d-electrons facilitate robust metal-metal bonding and interatomic interactions.
- The strength of these unpaired d-electrons enhances metal-metal bond formation, consequently increasing the enthalpy of atomization.
- Zinc (Zn), a 3d-series element, possesses the lowest enthalpy of atomization due to its filled \(3d^{10}\) orbital, leading to weaker metal-metal bonding.
- The strength of these unpaired d-electrons enhances metal-metal bond formation, consequently increasing the enthalpy of atomization.
- Zinc (Zn), a 3d-series element, possesses the lowest enthalpy of atomization due to its filled \(3d^{10}\) orbital, leading to weaker metal-metal bonding.
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