While studying photoelectric emission from a given surface, the wavelength of the incident radiation is changed from \(600\,\text{nm}\) to \(400\,\text{nm}\), keeping the intensity of radiation the same. Then :
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In photoelectric effect:
\[
K_{\max}=h\nu-\phi
\]
and
\[
eV_0=K_{\max}.
\]
Higher frequency (or lower wavelength) means higher stopping potential. Saturation current depends mainly on intensity.