Question

Which will make basic buffer?

• A. $100\, mL \,of\, 0.1\, M \,HCI\, + \,100\, mL\, of\, 0.1\, M\, NaOH$
• B. $100\, mL \,of\, 0.1\, M \,HCI \,+ \,100\, mL\, of\, 0.1\, M \,NaOH$
• C. $50 \,mL \,of\, 0 .1\, M \,NaOH\, + \,25 \,mL\, of \,0.1 M \,CH_3COOH$
• D. $100\, mL\, of\, 0.1 \,M \,CH_3COOH + 100\, mL 0.1\, MNaOH$

Answer 1

The Correct Option is A

 To determine which combination results in a basic buffer, we need to understand the concept of a buffer solution. A buffer solution is one that resists changes in its pH when an acid or base is added. Buffer solutions typically consist of a weak acid and its conjugate base, or a weak base and its conjugate acid.

For a basic buffer, we need to have a weak base and its conjugate acid. Let's analyze each option:

1. \(100 \, mL \, of \, 0.1\, M \, HCI\, + \,100\, mL\, of\, 0.1 \, M \, NaOH\)
2. \(50 \,mL \,of\, 0 .1\, M \,NaOH\, + \,25 \,mL\, of \,0.1\, M \,CH_3COOH\)
3. \(100 \,mL \,of\, 0.1\, M \,CH_3COOH + 100\, mL \,of\, 0.1\, M \, NaOH\)

Among the given options, \(50 \,mL \,of\, 0 .1\, M \,NaOH\, + \,25 \,mL\, of \,0.1 \,M \, CH_3COOH\) forms a basic buffer because it results in the formation of a weak base (CH₃COONa) and has some excess NaOH, helping resist changes in pH, thus acting as a basic buffer.