Step 1: Understanding the Concept:
The Hoffmann bromamide degradation reaction is a signature organic method used to convert a primary amide into a primary amine containing one fewer carbon atom. The pathway involves treating the primary amide with bromine ($\text{Br}_2$) in an aqueous or ethanolic solution of sodium hydroxide ($\text{NaOH}$).
Step 2: Key Formula or Approach:
The balanced chemical equation for the standard Hoffmann bromamide degradation is:
\[ \text{R-CONH}_2 + \text{Br}_2 + 4\text{NaOH} \rightarrow \text{R-NH}_2 + \text{Na}_2\text{CO}_3 + 2\text{NaBr} + 2\text{H}_2\text{O} \]
Let's evaluate each statement individually using this benchmark mechanism.
Step 3: Detailed Explanation:
- Statement A: According to the balanced equation, $1 \text{ mole}$ of primary amide reacts with $4 \text{ moles}$ of $\text{NaOH}$ and $1 \text{ mole}$ of $\text{Br}_2$. Statement A states that $2 \text{ moles}$ of $\text{Br}_2$ are consumed, which is incorrect. Thus, A is false.
- Statement B: Both aliphatic (alkyl) amides and aromatic (aryl) amides readily undergo this degradation to form corresponding primary amines. Thus, B is false.
- Statement C: The chief synthetic function of this reaction is the clean preparation of primary aliphatic or aromatic amines ($\text{R-NH}_2$). Thus, C is true.
- Statement D: The reaction mechanism strictly requires a primary amide ($\text{R-CONH}_2$) because it requires two acidic protons attached to the nitrogen to undergo the initial $N$-bromination and subsequent deprotonation stages. Secondary amides ($\text{R-CONHR}'$) do not undergo this transformation. Thus, D is false.
- Statement E: From the balanced reaction stoichiometry, the formed inorganic by-products are explicitly sodium carbonate ($\text{Na}_2\text{CO}_3$), sodium bromide ($\text{NaBr}$), and water ($\text{H}_2\text{O}$). Thus, E is true.
Reviewing our choices, only statements C and E are true.
Step 4: Final Answer:
The correct option is (3) which includes C and E only.