Step 1: Ambident nucleophile idea:
The nitrite anion has two attacking sites, O and N, and the product depends on the salt.
Step 2: Compare the salts:
KNO2 is ionic. O carries the negative charge and attacks, so R-ONO forms. $\text{AgNO}_2$ has a covalent Ag-N bond so N attacks to give $\text{R-NO}_2$.
Step 3: Check other options:
AgCN gives isocyanide, silver carboxylate gives esters. So option (C) matches the alkyl nitrite.
Final Answer:
Potassium nitrite is the reagent, option (C).
\[ \boxed{\text{Potassium nitrite (C)}} \]