Question:medium

Which reagent is used in the Reimer--Tiemann reaction to convert phenol to salicylaldehyde?

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Remember: Reimer--Tiemann reaction = Phenol + \(CHCl_3\) + \(NaOH\) → Salicylaldehyde.
Updated On: Apr 18, 2026
  • \(CHCl_3\) and \(NaOH\)
  • \(HNO_3\)
  • \(KMnO_4\)
  • \(HCl\)
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The Correct Option is A

Solution and Explanation

Step 1: Understanding the Question:
The question asks to identify the specific reagents for a named organic reaction.
The topic is Phenols.
Step 2: Key Formula or Approach:
The Reimer--Tiemann reaction involves the introduction of a \( -CHO \) group into the ortho-position of the benzene ring of phenol.
Step 3: Detailed Explanation:
In this reaction, Phenol reacts with Chloroform (\( CHCl_3 \)) in the presence of an alkali (\( NaOH \)).
This generates a dichlorocarbene intermediate, which attacks the phenoxide ion.
Subsequent hydrolysis leads to the formation of o-hydroxybenzaldehyde (Salicylaldehyde).
Step 4: Final Answer:
The required reagents are \( CHCl_3 \) and \( NaOH \).
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