Question

Which one of the followings has maximum number of atoms ?

• A. 1g of Ag(s) [Atomic mass of Ag = 108]
• B. 1g of Mg(s) [Atomic mass of Mg = 24]
• C. 1g of $O_2(g)$ [Atomic mass of O = 16]
• D. 1g of $Li(s)$ [Atomic mass of Li = 7]

Answer 1

The Correct Option is D

To determine which substance has the maximum number of atoms, we need to follow a step-by-step approach using the concept of moles.

1. The number of atoms in one mole of a substance is equal to Avogadro's number: \(6.022 \times 10^{23}\) atoms.
2. First, calculate the number of moles for each substance using the formula: \(n = \frac{m}{M}\), where \(n\) is the number of moles, \(m\) is the mass of the sample, and \(M\) is the molar mass of the element.
3. Calculate the moles for each element:

Substance	Atomic Mass	Moles Calculation	Moles
Ag	108	\(\frac{1}{108}\)	\(0.00926\)
Mg	24	\(\frac{1}{24}\)	\(0.04167\)
\(O_2\)	32 (since \(O_2\) is diatomic, use \(16 \times 2 = 32\))	\(\frac{1}{32}\)	\(0.03125\)
Li	7	\(\frac{1}{7}\)	\(0.14286\)

1. The number of moles is a direct measure of the number of atoms because one mole contains Avogadro's number of atoms.
2. From the table, 1g of Li has the maximum number of moles (\(0.14286\)), which corresponds to the maximum number of atoms.
3. Thus, among the given options, 1g of \(Li(s)\) [Atomic mass of Li = 7] has the maximum number of atoms.