Question:easy

Which one of the following reactions does not occur?

Show Hint

Remember the reactivity order of halogens: \[ F_2 \gt Cl_2 \gt Br_2 \gt I_2 \] A halogen can displace only the halide ions of elements below it in the group.
Updated On: Jun 16, 2026
  • \(2H_2O(l)+2F_2(g)\rightarrow 4HF(aq)+O_2(g)\)
  • \(2KF(aq)+Cl_2(g)\rightarrow 2KCl(aq)+F_2(g)\)
  • \(2KBr(aq)+Cl_2(g)\rightarrow 2KCl(aq)+Br_2(l)\)
  • \(2KI(aq)+Br_2(l)\rightarrow 2KBr(aq)+I_2(s)\)
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Recall the displacement rule.
A halogen can push out the halide of a halogen below it, because oxidising power falls down the group: $F_2 \gt Cl_2 \gt Br_2 \gt I_2$.

Step 2: Check option (A).
Fluorine is so strong it even oxidises water to oxygen, giving $HF$ and $O_2$. This reaction does occur.

Step 3: Check option (B).
Here chlorine is asked to push fluorine out of $KF$. But fluorine is stronger than chlorine, so chlorine cannot displace it. This reaction does not happen.

Step 4: Check option (C).
Chlorine is above bromine, so it easily displaces bromine from $KBr$. This works.

Step 5: Check option (D).
Bromine is above iodine, so it displaces iodine from $KI$. This works.

Step 6: Pick the impossible one.
Only option (B) breaks the rule, so it is the reaction that does not occur.
\[ \boxed{2KF(aq)+Cl_2(g)\rightarrow 2KCl(aq)+F_2(g)} \]
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