Step 1: Understanding the Concept:
This problem applies Coulomb's Law, which describes the electrostatic force between two point charges. The question is an optimization problem: we need to maximize the force, which means we need to maximize the product of the charges, given that their sum is constant in each case.
Step 2: Key Formula or Approach:
1. Coulomb's Law: The magnitude of the electrostatic force (F) between two point charges \( q_1 \) and \( q_2 \) separated by a distance r is:
\[ F = k \frac{|q_1 q_2|}{r^2} \]
where k is Coulomb's constant.
2. To maximize the force F for a fixed distance r, we need to maximize the product of the magnitudes of the charges, \( |q_1 q_2| \).
3. Notice that in all the given options, the sum of the two charges is the same:
- (A) 0.3 + 0.7 = 1.0
- (B) 0.1 + 0.9 = 1.0
- (C) 0.2 + 0.8 = 1.0
- (D) 0.5 + 0.5 = 1.0
- (E) 0.4 + 0.6 = 1.0
So, we have a fixed sum \( q_1 + q_2 = 1 \text{ C} \), and we want to maximize the product \( q_1 q_2 \).
Step 3: Detailed Explanation:
This is the same mathematical problem as in question 63. For a fixed sum, the product of two positive numbers is maximized when the numbers are equal.
Let \( q_1 + q_2 = S \). We want to maximize \( P = q_1 q_2 \).
Let \( q_1 = x \), then \( q_2 = S - x \). The product is \( P(x) = x(S-x) = Sx - x^2 \).
To find the maximum, we take the derivative and set it to zero:
\[ \frac{dP}{dx} = S - 2x = 0 \implies x = \frac{S}{2} \]
So, \( q_1 = S/2 \). Then \( q_2 = S - S/2 = S/2 \). The product is maximized when \( q_1 = q_2 \).
In our case, the sum is \( S=1.0 \text{ C} \). The product is maximized when:
\[ q_1 = q_2 = \frac{1.0}{2} = 0.5 \text{ C} \]
Let's check the products for all options:
- (A) 0.3 × 0.7 = 0.21
- (B) 0.1 × 0.9 = 0.09
- (C) 0.2 × 0.8 = 0.16
- (D) 0.5 × 0.5 = 0.25
- (E) 0.4 × 0.6 = 0.24
The largest product is indeed 0.25, which corresponds to the charges 0.5 C and 0.5 C.
Step 4: Final Answer:
The pair of charges 0.5 C and 0.5 C will experience the maximum force.