To detect hash table collisions, compute the hash function \(H(I) = \text{Data element} \mod \text{Hash Table Size}\) for each element. The hash table size is 7.
1. Hash value calculation for each element:
- 7: \(7 \mod 7 = 0\)
- 5: \(5 \mod 7 = 5\)
- 17: \(17 \mod 7 = 3\)
- 13: \(13 \mod 7 = 6\)
- 9: \(9 \mod 7 = 2\)
- 27: \(27 \mod 7 = 6\)
- 31: \(31 \mod 7 = 3\)
- 25: \(25 \mod 7 = 4\)
- 35: \(35 \mod 7 = 0\)
2. Collision identification:
- Element 27 collides with 13 at hash index 6.
- Element 31 collides with 17 at hash index 3.
- Element 35 collides with 7 at hash index 0.
- Element 25 has a unique hash index 4, thus no collision.
3. Conclusion:
Elements that will create collisions are:
- (A) Element 27
- (C) Element 35
- (D) Element 31
The correct selection is: (A), (C), and (D) only.