Question:medium

Which of the following substances show the highest colligative properties?

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Colligative properties increase with the number of particles in solution. More dissociation leads to stronger effects.
Updated On: Jan 13, 2026
  • 0.1M BaCl$_2$
  • 0.1M AgNO$_3$
  • 0.1M urea
  • 0.1M (NH$_4$)$_3$PO$_4$
Show Solution

The Correct Option is D

Solution and Explanation

Step 1: Colligative Property Fundamentals
- Colligative properties are determined by the quantity of particles in a solution, not their chemical identity. 
- The van't Hoff factor (\(i\)) quantifies the dissociation of a molecule into ions. 
Step 2: Ion Calculation for Dissociation 
BaCl$_2$ yields 3 ions: one Ba$^{2+}$ and two Cl$^-$. 
AgNO$_3$ yields 2 ions: one Ag$^+$ and one NO$_3^-$. 
Urea is a non-dissociating solute, thus \( i = 1 \).
(NH$_4$)$_3$PO$_4$ yields 4 ions: three NH$_4^+$ and one PO$_4^{3-}$. 
Step 3: Determining the Greatest Colligative Effect 
A higher ion count leads to more pronounced colligative properties. 
(NH$_4$)$_3$PO$_4$, producing 4 ions, exhibits the most significant colligative effect.
Therefore, the correct designation is (D).

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