Let's examine each statement to determine which are correct:
Regular languages are closed under intersection. This means that if you have two regular languages, their intersection is also a regular language. This follows from the properties of regular languages and can be proven using finite automata. Therefore, this statement is correct.
Context-free languages are not closed under intersection. While there are some specific cases where the intersection of context-free languages could be context-free, in general, it is not guaranteed. Therefore, this statement is incorrect.
Recursive languages are closed under intersection. This means the intersection of two recursive languages is always a recursive language. Hence, this statement is correct.
Recursively enumerable languages are not closed under intersection. This means that even if each of the two languages is recursively enumerable, their intersection might not be. Therefore, this statement is incorrect.
The correct answer is: "The intersection of two regular languages is regular." and "The intersection of two recursive languages is recursive."
Let \(A\) be the adjacency matrix of the given graph with vertices \(\{1,2,3,4,5\}\). 
Let \(\lambda_1, \lambda_2, \lambda_3, \lambda_4, \lambda_5\) be the eigenvalues of \(A\) (not necessarily distinct). Find: \[ \lambda_1 + \lambda_2 + \lambda_3 + \lambda_4 + \lambda_5 \;=\; \_\_\_\_\_\_ . \]