Question

Which of the following quantity has the dimension of length? (where \(h\) is Planck’s constant, \(m\) is the mass of electron and \(c\) is the velocity of light):

• A. \(\frac{hc}{m}\)
• B. \(\frac{h}{mc^2}\)
• C. \(\frac{h^2}{m^2c^2}\)
• D. \(\frac{h}{mc}\)

Hint:

In dimensional analysis, break down the dimensions of each term in the equation and simplify them to check for consistency with the required dimension.

Answer 1

The Correct Option is D

Step 1: Begin by stating the dimensional formulas for the physical quantities:

• \( h \) (Planck’s constant): \([h] = [ML^2T^{-1}]\).
• \( m \) (mass of the electron): \([m] = [M]\).
• \( c \) (velocity of light): \([c] = [LT^{-1}]\).

Step 2: Next, determine the dimensions of each provided option.

For option \( \frac{hc}{m} \):

\[ \left[ \frac{hc}{m} \right] = \frac{[ML^2T^{-1}][LT^{-1}]}{[M]} = [L^2T^{-2}] \]

This does not represent the dimension of length.

For option \( \frac{h}{mc^2} \):

\[ \left[ \frac{h}{mc^2} \right] = \frac{[ML^2T^{-1}]}{[M][L^2T^{-2}]} = [T] \]

This corresponds to the dimension of time, not length.

For option \( \frac{h^2}{m^2c^2} \):

\[ \left[ \frac{h^2}{m^2c^2} \right] = \frac{[M^2L^4T^{-2}]}{[M^2][L^2T^{-2}]} = [L^2] \]

This represents the dimension of area, not length.

For option \( \frac{h}{mc} \):

\[ \left[ \frac{h}{mc} \right] = \frac{[ML^2T^{-1}]}{[M][LT^{-1}]} = [L] \]

This corresponds to the dimension of length.