Login / Register
Question:medium

Which of the following pairs of ions will have same spin only magnetic moment values within the pair?
A. Zn2+, Ti2+
B. Cr2+, Fe2+
C. Ti3+, Cu2+
D. V2+, Cu+
Choose the correct answer from the options given below:

Updated On: Nov 26, 2025
  • C and D only
  • A and D only
  • A and B only
  • B and C only
Hide Solution

The Correct Option is D

Solution and Explanation

The spin-only magnetic moment is computed via the formula:

\[\mu = \sqrt{n(n+2)}\]

In this equation, 'n' represents the count of unpaired electrons, and 'μ' denotes the magnetic moment expressed in Bohr magnetons.

The objective is to ascertain the number of unpaired electrons for each specified ion:

  1. Zn2+ (d10), Ti2+ (d2): Zn2+ possesses 0 unpaired electrons, whereas Ti2+ has 2.
  2. Cr2+ (d4), Fe2+ (d6): Cr2+ has 4 unpaired electrons, and Fe2+ also has 4.
  3. Ti3+ (d1), Cu2+ (d9): Ti3+ contains 1 unpaired electron, and Cu2+ also has 1.
  4. V2+ (d3), Cu+ (d10): V2+ exhibits 3 unpaired electrons, while Cu+ has 0.

Consequently, the pairs exhibiting identical spin-only magnetic moments are B (comprising Cr2+ and Fe2+) and C (comprising Ti3+ and Cu2+).

Was this answer helpful?
0

Top Questions on Coordination chemistry

Questions Asked in NEET (UG) exam