For ions sharing the same electron configuration, ionic radius shrinks as the ionic charge increases. The order is:
- \( Al^{3+} \) exhibits the smallest ionic radius because of its 3+ charge. This is succeeded by \( Mg^{2+} \) (2+ charge), and finally \( N^{3-} \) (3- charge), which has the largest radius due to its negative charge.
The correct sequence is therefore \( Al^{3+} < Mg^{2+} < N^{3-} \).