Step 1: Charge check first:
The formula has no charge on it. So the complex is neutral, and the metal keeps its normal name, platinum. Any option ending in "platinate" can be dropped. That removes option 3.
Step 2: Oxidation state:
Charges: two $NH_3$ give $0$, one $Cl^{-}$ gives $-1$, one $NO_2^{-}$ gives $-1$. For the sum to be $0$, $Pt$ must be $+2$. Option 2, which says $(III)$, is dropped.
Step 3: Ligand names:
The ligand $NO_2^{-}$ is nitrito (nitrite) when named as a ligand. "Nitrido" refers to $N^{3-}$, so option 4 is dropped. Option 4 also misspells chlorido as "chloride".
Step 4: Final form:
Alphabetical order a, c, n gives: diammine, chlorido, nitrito-N, then platinum(II).
Final Answer:
\[ \boxed{\text{Diamminechloridonitrito-N-platinum(II)}} \]