Step 1: Classification rule:
Count the carbon atoms joined to the carbon that holds the -OH: one carbon means primary, two means secondary, three means tertiary.
Step 2: Apply to the figures:
(A) CH2OH on ring: one carbon neighbour (the ring), primary.
(B) CH(OH) with ring and ethyl: two carbon neighbours, secondary.
(C) CH(OH) with ring and methyl: two neighbours, secondary.
(D) C(OH) with ring and two methyls: three carbon neighbours, tertiary.
Step 3: Benzylic check:
In all four the carbinol carbon is attached to the ring, but only (D) is tertiary.
Final Answer:
Option (D) is the tertiary benzylic alcohol.
\[ \boxed{\text{(D)}} \]