Step 1: Define a catalyst.
A catalyst speeds up a reaction by offering a different route with lower activation energy. It isn't permanently changed in the process.
Step 2: Verify each statement.
(1) True — Decreased \(E_a\) (see Arrhenius equation: \(k = A e^{-E_a/RT}\)).
(2) True — Rate increases because \(k\) is larger.
(3) True — Only small quantities are needed as the catalyst is regenerated (high turnover).
(4) False — A catalyst is not used up; its chemical composition remains unchanged.
Final Answer: \[ \boxed{\text{A catalyst is used up during the reaction}} \]