Question:medium

Which of the following is/are correct with respect to the energy of atomic orbitals of a hydrogen atom? 
(A) \( 1s<2s<2p<3d<4s \) 
(B) \( 1s<2s = 2p<3s = 3p \) 
(C) \( 1s<2s<2p<3s<3p \) 
(D) \( 1s<2s<4s<3d \)
 Choose the correct answer from the options given below:

Show Hint

Remember that the energy of orbitals increases with the principal quantum number, but for orbitals within the same shell, the order depends on the angular quantum number (l).
Updated On: Mar 25, 2026
  • (A) and (C) only
  • (A) and (B) only
  • (C) and (D) only
  • (B) and (D) only
Show Solution

The Correct Option is A

Solution and Explanation

For hydrogen-like atoms, orbital energy increases with the principal quantum number (n). Within a given shell, orbitals with higher angular momentum (l) possess greater energy.

  • (A) is correct: \( 1s<2s<2p<3d<4s \).
  • (B) is incorrect due to \( 2s eq 2p \) and \( 3s eq 3p \).
  • (C) is correct, adhering to the established orbital order for hydrogen.
  • (D) is incorrect; \( 4s \) has lower energy than \( 3d \).

The correct options are (A) and (C).

Was this answer helpful?
1


Questions Asked in JEE Main exam