Question:medium

Which of the following is applicable for isothermal process?

Show Hint

In an isothermal process the temperature is constant, so the internal energy change is zero and the first law gives heat equal to work.
Updated On: Nov 12, 2026
  • \(W=-Q\)
  • \(-\Delta U=-W\)
  • \(\Delta U=Q_{v}\)
  • \(Q_{p}=\Delta U+P_{ext}\Delta V\)
Show Solution

The Correct Option is A

Solution and Explanation

Step 1: Compare the options
Option (C), $\Delta U=Q_v$, holds for a constant-volume process. Option (D) is the form for a constant-pressure process.

Step 2: Check option B
Option (B), $-\Delta U=-W$, means $\Delta U=W$, which holds for an adiabatic process where $Q=0$.

Step 3: Select
Only $W=-Q$ follows from $\Delta U=0$, so option (A) is correct.

Final Answer:
The relation is $W=-Q$. \[ \boxed{\text{(A) }W=-Q} \]
Was this answer helpful?
0